Displacement Calculator
Find displacement from velocity and time, initial and final velocity, or constant acceleration, plus the no-time stopping-distance formula d = (v^2 - u^2)/2a. Reports average velocity, final velocity and time, with metric and imperial units.
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Physics
Mechanics
Displacement Calculator
Find displacement from velocity and time, initial and final velocity, or constant acceleration, plus the no-time stopping-distance formula d = (v^2 - u^2)/2a. Reports average velocity, final velocity and time, with metric and imperial units.
Displacement Calculator
Choose your scenario
Choose what you know: a steady velocity, a change from one velocity to another, a constant acceleration, or velocities with an acceleration but no time.
Enter what you know
Only the boxes your chosen scenario needs are shown. Set each field's unit with the switch on its right; the answer updates as you type.
Result
Moving at a steady 10 m/s for 5 sec covers a displacement of 50 m. With constant velocity the displacement is simply the velocity multiplied by the time.
Displacement is the amount and direction of change in an object's position from its starting point. It is a straight line distance between the start and end points and can be expressed in various units such as meters, feet or miles.
This calculator will determine the displacement in four different ways depending on what information is available. You can input a constant velocity and time, initial and final velocities or acceleration. Alternatively you can enter a change in velocity without specifying a time. In these cases the calculator will also calculate the average velocity, final velocity or corresponding time in addition to the displacement.
Displacement is not the same as distance.
Distance is the entire length of the path traveled by an object. Displacement on the other hand, is the straight line distance between the starting and ending point and also includes direction.
For example, if you drive five kilometres to work and then another five kilometres back home, the total distance traveled is ten kilometres. However, since your final location is the same as where you started from, the displacement is zero.
As the displacement has a direction, it is a vector and can have negative values. A negative value simply means that the object ends up on the opposite side of its starting point. The displacement can never be larger than the distance traveled; at most they are equal. This only applies if the motion always happens in a straight line though.
Four equations for displacement.
These four equations all derive from the equations of uniformly accelerated motion, which are commonly referred to as SUVAT equations. As each equation uses a different combination of known quantities, a calculation tool will first ask what information is known.
1. Constant speed:
If the speed is constant then displacement is equal to velocity times time.
A car traveling at a speed of 20 meters per second for 5 seconds will cover a distance of 100 meters, which is the product of 20 and 5. This is an equation used in everyday road traffic. If a vehicle travels at a speed of 70 miles per hour for 2 hours, then the displacement is 140 miles.
2. From initial and final speed.
If the speed is changing constantly, then the average speed will be exactly halfway between the initial and final speeds, and the distance traveled will be that average speed multiplied by the time.
In this case u is the initial velocity and v is the final velocity. If a sprinter accelerates from an initial velocity of 20 meters per second to a final velocity of 23 meters per second in 45 seconds, then the distance traveled is half of the product of 43 and 45, which equals 967.5 meters. The formula can also be rearranged to find time given a known distance: t = 2d / (u + v).
3. From acceleration:
If the initial velocity, acceleration and time are known, then the distance can be calculated by adding the constant speed portion to the accelerated portion.
If an object is released from rest it will fall due to gravity at a rate of about 9.81 meters per second squared. The distance fallen after two seconds would be half the product of 9.81 and 4, or about 19.6 meters. You can use Earth's acceleration directly by entering "g" in the acceleration field.
4. When time is unknown.
Sometimes even when speed and acceleration are known it is not clear how long the change in speed lasts for. Here is a formula for braking distance that does not require time.
Suppose a car is moving at a speed of 30 meters per second and comes to rest with retardation of 6 meters per second squared. The distance covered by the car before coming to rest is 75 meters, which is equal to 900 divided by 12. The calculator also gives out the time taken for stopping, which is (v minus u) divided by a.
To use this calculator:
Start with the main menu and select the scenario that matches your question. The input fields will change accordingly so that only the measurements required for this scenario are shown.
If you enter known values, the calculator will instantly show you the distance traveled. Each field has a unit conversion option so that for example you can enter speed in miles per hour and time in hours to get the distance traveled in miles. All conversions are done by the calculator.
If the motion is going backwards or an object is slowing down, leave the sign of the velocity or acceleration alone. This sign will keep track of direction until you get to your final answer.
Examples:
These examples use integers so that you can verify the calculations manually.
Scenario | Known values | Displacement |
|---|---|---|
Constant velocity | v = 10 m/s, t = 5 s | 50 m |
Average velocity | u = 0, v = 20 m/s, t = 5 s | 50 m |
Constant acceleration | u = 0, a = 2 m/s2, t = 5 s | 25 m |
Free fall | u = 0, a = 9.81 m/s2, t = 2 s | 19.6 m |
Stopping distance | u = 30 m/s, v = 0, a = -6 m/s2 | 75 m |
A car traveling at a constant speed and a car traveling with average speed both travel the same distance of 50 meters. The average speed during acceleration from 0 to 20 meters per second is 10 meters per second, which is the same as a constant speed of 10 meters per second.
Average and final speed:
If the calculation tools include time data, average speed is also given. This corresponds to a single constant speed that would cover the same distance in the same amount of time. Average speed is distance divided by time.
In acceleration scenarios, the final velocity is also stated. This is the speed of the object at the end of its motion and is calculated based on the formula v = u + a t. These additional results allow for a better understanding of a problem involving motion.
Units of Displacement
Since the displacement is a type of length, any unit of length can be used. The meter is the SI unit, while miles are convenient for road trips and feet are good for working on cars.
Unit | Symbol | In metres |
|---|---|---|
Millimetre | mm | 0.001 |
Centimetre | cm | 0.01 |
Metre | m | 1 |
Kilometre | km | 1000 |
Foot | ft | 0.3048 |
Yard | yd | 0.9144 |
Mile | mi | 1609.344 |
Why displacement is important
Displacement is the starting point for nearly all motion problems in physics. It's used to calculate where a projectile will land, how far a car travels before coming to rest, and how high an elevator goes between two floors.
Engineers use displacement to calculate braking distances and safe following distances, navigators plot straight-line routes between two points, and animators move objects smoothly across the screen. In all of these cases it is important to consider the net change in position, not the winding path taken to get there.
Common Mistakes
The most common mistake is to confuse displacement with distance. If an object reverses direction during its motion, these two values are different; only the linear change in position represents the displacement.
Be careful about the sign of velocity and acceleration. A car that is slowing down has a negative acceleration relative to its direction of motion. If you get the sign wrong, it will change the sign of your answer. Make sure you use consistent units or do the conversion yourself. Don't mix miles per hour with seconds.
This tool is for general educational purposes and solving everyday problems. For technical applications, safety issues or other risky activities verify the values against the standards and data required by your project.
Frequently asked questions
- What formula is used to calculate displacement?
The formula used depends on the known quantities. At constant velocity, displacement is the product of velocity and time, so d = v*t. When speed is changing constantly, the displacement is the product of average speed (the sum of initial and final speeds divided by two) and time, so d = ((u+v)/2)*t. For constant acceleration, displacement is d = u*t plus half of a.*t2. This calculator will select the correct formula based on the scenario you choose.
- How do you calculate displacement with velocity and time?
At constant speed you multiply the speed by time. The formula is d=v*t. For example if a car travels at 20 meters per second for 5 seconds it will travel 100 meters. On roads, using the same rule, we can convert a trip of 70 miles per hour over two hours into a distance of 140 miles. If speed changes you use average of initial and final speeds.
- How to calculate displacement from acceleration?
The formula is d = u*t plus one half a t squared, where u is the initial velocity, a is acceleration and t is time. If an object falls from rest due to gravity, u will be 0, and a will be approximately 9.81 meters per second squared. So after two seconds, the distance fallen would be half of 9.81 times 4, or about 19.6 meters. You can use Earth's gravity if you choose a constant acceleration scenario and set the value for acceleration to g.
- Can the displacement be greater than the distance?
No. Displacement is the straight line distance between the starting and ending point while distance traveled is the total length of the path followed by an object. Since a straight line is always the shortest distance between two points, displacement can be equal to or less than distance traveled but never greater. This only applies if an object moves in a straight line without reversing direction.
- Can the shift be negative or zero?
Yes. Since displacement is a vector quantity, its sign indicates the direction. A negative displacement means that the object ends up on the opposite side of the starting point. If the object returns to the starting point, then the displacement is zero. For example, if you drive from your home to work and back again, the total distance traveled is not zero but the displacement is zero.
- What is the difference between displacement and distance?
The distance is the length of the path between two points and a scalar quantity with no direction. The displacement is the change in position from the starting point to the end point measured along a straight line and it is a vector quantity with both magnitude and direction. For example, if you walk 3 meters east and then 4 meters north, your distance traveled is 7 meters while your displacement is 5 meters northeast which is the length of the straight line that closes the triangle.
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Disclaimer: This calculator is provided for general informational and educational purposes only. Our calculators are under active development, and results may be inaccurate, incomplete, or unsuitable for your situation. Always verify the figures independently and seek advice from a qualified professional before relying on them. We make no warranties and accept no liability for any loss or decision arising from use of this tool.
References
- Wikipedia: Displacement (geometry)
Displacement as a vector, the straight line from initial to final position.
- Wikipedia: Equations of motion
The SUVAT equations for motion under constant acceleration.
- Wikipedia: Kinematics
Displacement, velocity and acceleration and how they relate.